Let'S call this point x y and the coordinates of x y are such that if you take 1 minus x and multiply that by 2, it's going to be the same thing as 4 minus x, okay. So the slope here m is negative 1 and we want to get the coordinates of this point. So this equation is simply y equals x and the line that is perpendicular to it has a slope of negative negative 1. So the slope of this line is 1 and, as you can see, the x value is the same as the y value. Changing is 4 minus 1, and change in x is 4 minus 1 to 3 over 3 point. Minus 1 and 1 minus 1 that makes 3 change in white. So we simply need the equation of this line, such that there will be 2 units and 1 unit respectively, okay, so the first thing we need to do is to get the equation of the line that is draining these 2 points. So this is for form, and this at the point here is 11, so you want the points to be twice as far from 44 to lisita for 4 and 11, so twice as far as twice as far from 4 form as from 11 point. As from 11, only set the equation up and do not simplify okay, so we're going to find the question of the set of work points that are twice as far from 4 form, so i'm just going to sketch for form. If we knew where the point is passing through now, then finally were finding the equation of the set of all points that are twice as far from 4 form. Where c is the is y intercept? So, in this case, we don't know where it's passing through so c would have to be obtained. So the slope intercept form, so it's going to be y equals negative 1 over 4 x plus c. Intercept form is y equals x, plus c, and the line that is perpendicular to this has a slope that is a negative reciprocal, which is negative, 1 over 4 point, and it's so that's the equation of the length that is perpendicular to this okay. Perpendicular to l 1 in the slope intercept form the slope. The point slope form max we're going to write the equation of the line. In this case, 3 equals the slope form and then we have x minus x 1, which is 2. So the point slope form takes the form y minus y 1 equals m x, minus x, 1 point, and so what we're going to have here is y minus y 1. So the slope of the line and slope of the line is 4 and we want the equation of the line in the slope. Next, using the slope of the line to write the equation of this line in the slope point form. So you want to get the angle there increase to get that we have to use the term, so the tangent of theta is the opposite of the adjacent, and so what we want to do is to get the tan inverse of 4 and write it up to The nearest degree, so the tarn in this form is 75.96, can run it up to 40 or to 7076 degrees. So this is this change in y, and this is the brown change in x. Okay, so this is a it's a rising line and what we want to get is the inclination of the slope to the nearest degree. So this, if you can sketch this line, this is a rising line. Next we're going to find the inclination of the slope to the nearest degree degree. So what we have before y 3 minus 7 over 2 minus 3- this equals negative 4 over negative 1 and that equals 4. The first part of the question requires us to find the slope of the line passing through the points, so the slope of the line is given by the change in y, say: y 1 minus y 2 change in x, x, 1, minus x, 2. In this question, we are given that a slant line l 1 is drawn through the points a and a 23 and 37 point we're going to answer the questions that follow based on this information.
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